Caso II ; RAB2
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Questa volta R5 ed R6 sono collegate in serie : |
| RS1= R5 + R6 = 220 + 820 = 1040 Ω = 1.04 kΩ |
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Resterà : |
| RP1 = ( RS1* R4 ) / ( RS1+ R4 ) = ( 1.04 * 12 ) / ( 1.04 +12 ) = 12.48 / 13.04 = 0.957 kΩ = 957 Ω |
RS2 = RP1 + R3 = 0.957 + 3.9 = 4.857 kΩ = 4857 Ω
RP2 = ( RS2* R2 ) / ( RS2+ R2 ) = ( 4.857 * 1.8 ) / ( 4.857 + 1.8 ) = 8.743 / 6.657 = 1.313 kΩ = 1313 Ω
RS3 = RP2 + R1 = 1313 + 330 = 1643 Ω = 1.643 kΩ
RS3 = RAB2 = 1.643 kΩ
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